The distributive law
a(b + c) = ab + ac. The outside factor reaches every inside term. 3(x + 2) = 3x + 6.
Why it works
3 rows of (x + 2) is 3 xs and 3 twos.
Simplifying · One Variable · B9
To remove a bracket, multiply the factor by every term inside: 3(x + 2) = 3x + 6. Miss a term and the answer is wrong.
Watch it simplify
3(x + 2): 3·x = 3x and 3·2 = 6, so 3x + 6.
Distribute
Multiply out the brackets — every term inside by the factor in front.
Your turn
Type the simplest form (e.g. 6x + 5). Use ^ for powers.
a(b + c) = ab + ac. The outside factor reaches every inside term. 3(x + 2) = 3x + 6.
Why it works
3 rows of (x + 2) is 3 xs and 3 twos.
3(x - 6)
Distribute
Multiply out the brackets — every term inside by the factor in front. → 3x - 18
7(x + 6)
Distribute
Multiply out the brackets — every term inside by the factor in front. → 7x + 42
7(x + 4)
Distribute
Multiply out the brackets — every term inside by the factor in front. → 7x + 28
3(x + 2) = 3x + 2 (only the first term).
Multiply BOTH: 3x + 6.
3(x + 2) = 3x · 6.
Distribute as a sum: 3x + 6.
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t₁ = 5, d = 3 and t1=5,d=3 both count. For a list of numbers, separate them with commas (e.g. 3, 10, 17).Simplify 3(x - 6)
Simplify 4(x - 2)
Simplify 4(x + 2)
Simplify 4(x + 5)
Simplify 7(x + 6)
Simplify 5(x - 6)
Simplify 8(x + 8)
Simplify 7(x - 3)
Simplify 7(x + 4)
Simplify 5(x + 7)
Simplify 8(x - 4)
Simplify 9(x + 4)