Subtract the difference
If the x’s match, subtract the y’s; if the y’s match, subtract the x’s. Take the absolute value.
Why it works
|6 − 1| = 5 units apart.
Graphs · On the grid · 2.2
For two points on the same horizontal or vertical line, the distance is the difference of the changing coordinates. (2, 1) to (2, 6): same x, so distance = |6 − 1| = 5.
Watch the method
(2, 1) to (2, 6) → |6 − 1| = 5.
Vertical distance
The points share an x, so subtract the other coordinates.
Your turn
Type a number, e.g. 5.
If the x’s match, subtract the y’s; if the y’s match, subtract the x’s. Take the absolute value.
Why it works
|6 − 1| = 5 units apart.
Find the distance between (2,-2) and (2,-4).
Vertical distance
The points share an x, so subtract the other coordinates. |-4 - -2| = 2
Find the distance between (-3,-3) and (1,-3).
Horizontal distance
The points share a y, so subtract the other coordinates. |1 - -3| = 4
Find the distance between (5,2) and (-4,2).
Horizontal distance
The points share a y, so subtract the other coordinates. |-4 - 5| = 9
Adding the coordinates.
Subtract to find the gap.
Forgetting the absolute value.
Distance is never negative.
12 problems across three tiers. Auto-graded on submit. Hints and a full walkthrough on every question. Your work is saved on this device — sign in to keep it across devices.
t₁ = 5, d = 3 and t1=5,d=3 both count. For a list of numbers, separate them with commas (e.g. 3, 10, 17).Find the distance between (-4,5) and (2,5).
Find the distance between (-5,3) and (-1,3).
Find the distance between (5,-5) and (5,4).
Find the distance between (-4,-1) and (1,-1).
Find the distance between (2,-1) and (2,1).
Find the distance between (5,2) and (-1,2).
Find the distance between (5,2) and (3,2).
Find the distance between (3,5) and (1,5).
Find the distance between (-2,5) and (5,5).
Find the distance between (-4,-1) and (-4,-2).
Find the distance between (-5,2) and (-5,-4).
Find the distance between (3,5) and (3,-2).