Built from smaller rules
÷6 needs both the ÷2 and ÷3 tests; ÷4 looks at the last two digits.
Why it works
24 is a multiple of 4, so 124 is too.
Factors · Factors · 1.4
Some rules combine others: a number is divisible by 6 if it’s divisible by BOTH 2 and 3; divisible by 4 if its last two digits form a multiple of 4.
Watch the method
124 → last two digits 24, a multiple of 4.
Divisibility by 4
Check: the last two digits form a multiple of 4.
÷6 needs both the ÷2 and ÷3 tests; ÷4 looks at the last two digits.
Why it works
24 is a multiple of 4, so 124 is too.
Is 587 divisible by 4? (the last two digits form a multiple of 4)
Answer
No
Is 913 divisible by 4? (the last two digits form a multiple of 4)
Answer
No
Is 271 divisible by 2? (the last digit is even)
Answer
No
Checking only ÷2 for ÷6.
÷6 needs ÷2 AND ÷3.
Using the whole number for ÷4.
Just the last two digits.
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t₁ = 5, d = 3 and t1=5,d=3 both count. For a list of numbers, separate them with commas (e.g. 3, 10, 17).Is 837 divisible by 3? (the digit sum is divisible by 3)
Is 934 divisible by 9? (the digit sum is divisible by 9)
Is 771 divisible by 9? (the digit sum is divisible by 9)
Is 449 divisible by 2? (the last digit is even)
Is 546 divisible by 4? (the last two digits form a multiple of 4)
Is 573 divisible by 2? (the last digit is even)
Is 627 divisible by 10? (the last digit is 0)
Is 349 divisible by 6? (it is divisible by both 2 and 3)
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Is 651 divisible by 5? (the last digit is 0 or 5)
Is 962 divisible by 2? (the last digit is even)
Is 672 divisible by 2? (the last digit is even)