When x disappears
If both sides reduce to a false statement, no solution; to a true statement, infinitely many.
Why it works
1 = 5 is never true; 2 = 2 is always true.
Solving Equations · Variables on both sides · 4.3
Sometimes the variable cancels. If the constants then disagree (2x + 1 = 2x + 5 → 1 = 5), there is NO solution. If they agree (2(x+1) = 2x + 2 → 2 = 2), EVERY value works — infinitely many solutions.
Watch the method
2x + 1 = 2x + 5 → 1 = 5, impossible → no solution.
The equation
Solve for x — find the value that makes both sides equal.
No solution
The variable cancels and the constants disagree — no value of x works.
If both sides reduce to a false statement, no solution; to a true statement, infinitely many.
Why it works
1 = 5 is never true; 2 = 2 is always true.
How many solutions does 5x + 4 = 5x + 8 have?
Answer
No solution
How many solutions does 3x + 2 = 3x + 5 have?
Answer
No solution
How many solutions does 2x + 3 = 2x + 9 have?
Answer
No solution
Writing x = 0 when x cancels.
A cancelled x means none or all, not zero.
Stopping before checking the constants.
Compare the leftover constants.
12 problems across three tiers. Auto-graded on submit. Hints and a full walkthrough on every question. Your work is saved on this device — sign in to keep it across devices.
t₁ = 5, d = 3 and t1=5,d=3 both count. For a list of numbers, separate them with commas (e.g. 3, 10, 17).How many solutions does 5x + 4 = 5x + 5 have?
How many solutions does 4x + 4 = 4x + 5 have?
How many solutions does 3x + 3 = 3x + 9 have?
How many solutions does 4x + 1 = 4x + 5 have?
How many solutions does 5x + 4 = 5x + 8 have?
How many solutions does 2x + 2 = 2x + 5 have?
How many solutions does 4(x + 1) = 4x + 4 have?
How many solutions does 2x + 4 = 2x + 7 have?
How many solutions does 5(x + 1) = 5x + 5 have?
How many solutions does 2x + 3 = 2x + 7 have?
How many solutions does 3(x + 3) = 3x + 9 have?
How many solutions does 2x + 3 = 2x + 8 have?